What Is The Answer Of This 2\Xd7\Xb2-8\Xd7?,S\Xb2+8s+12?,9+\Xb2-4? Plss

What is the answer of this 2ײ-8×?,s²+8s+12?,9+²-4? Plss

Answer:

2x^2-8x

2x^2=8x

2x 2x

x=4

**If only for factors rhen 2x(x-4)

s^2+8s+12

(s+6)(s+2)

Usually, any number on the position of 12, will be the factors you need to use that will result to the middle number.

9t^2-4(Assuming its a typo for letter t)

9t^2=4

9 9

t^2=4/9

Get the square root of both sides.

t=+/-2/3


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