What Is The Answer Of This 2\Xd7\Xb2-8\Xd7?,S\Xb2+8s+12?,9+\Xb2-4? Plss
What is the answer of this 2ײ-8×?,s²+8s+12?,9+²-4? Plss
Answer:
2x^2-8x
2x^2=8x
2x 2x
x=4
**If only for factors rhen 2x(x-4)
s^2+8s+12
(s+6)(s+2)
Usually, any number on the position of 12, will be the factors you need to use that will result to the middle number.
9t^2-4(Assuming its a typo for letter t)
9t^2=4
9 9
t^2=4/9
Get the square root of both sides.
t=+/-2/3
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